'Run it back': Rob Gronkowski earns mega payday to stay with Tom Brady

Robert Gronkowski has reportedly signed a one-year deal worth $13 million to remain at the Tampa Bay Buccaneers with legendary quarterback Tom Brady.

Gronkowski came out of a one-year retirement and joined Brady at his new franchise for the 2020 season.

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The 31-year-old put up solid stats, catching 45 passes for 623 yards and seven touchdowns in 2020.

He also put in a stellar performance in the Super Bowl to help lift the Buccaneers over the Kansas City Chiefs with two touchdowns.

While it is unclear how long Gronkowski will play, Brady just signed a year-extension on his contract to see him through to 2022 with Tampa Bay.

Gronkowski teases Brady split

But, only just before signing, Gronkowski teased he could be willing to split with Brady.

Speaking on 10 Questions with Kyle Brandt, Gronkowski said he wanted to 'dip his toes' into the free agent market.

“With the free agency process, you just never know what may happen,” he told Brandt.

“There’s some other teams interested out there, too. I’ve also never been a part of the free-agency process, so I actually want to dip my toes in, just to see what’s out there.

“I want to be a free agent every year, so if I dip my toes in this year, see what’s out there, see how it works, even if I do go back to the Bucs … I’ll know how free agency works and I’ll know how teams come after you.

"Then I’ll have that much more of an advantage every single year.”

Tampa Bay have also moved to resign star pass-rusher Shaquil Barrett.

Barrett agreed to a four-year deal worth a reported $93 million.

with Chris Kwik - Yahoo Sport US